Server IP : 85.214.239.14 / Your IP : 3.140.195.8 Web Server : Apache/2.4.62 (Debian) System : Linux h2886529.stratoserver.net 4.9.0 #1 SMP Tue Jan 9 19:45:01 MSK 2024 x86_64 User : www-data ( 33) PHP Version : 7.4.18 Disable Function : pcntl_alarm,pcntl_fork,pcntl_waitpid,pcntl_wait,pcntl_wifexited,pcntl_wifstopped,pcntl_wifsignaled,pcntl_wifcontinued,pcntl_wexitstatus,pcntl_wtermsig,pcntl_wstopsig,pcntl_signal,pcntl_signal_get_handler,pcntl_signal_dispatch,pcntl_get_last_error,pcntl_strerror,pcntl_sigprocmask,pcntl_sigwaitinfo,pcntl_sigtimedwait,pcntl_exec,pcntl_getpriority,pcntl_setpriority,pcntl_async_signals,pcntl_unshare, MySQL : OFF | cURL : OFF | WGET : ON | Perl : ON | Python : ON | Sudo : ON | Pkexec : OFF Directory : /srv/modoboa/env/lib64/python3.5/site-packages/future/builtins/ |
Upload File : |
""" ``python-future``: pure Python implementation of Python 3 round(). """ from future.utils import PYPY, PY26, bind_method # Use the decimal module for simplicity of implementation (and # hopefully correctness). from decimal import Decimal, ROUND_HALF_EVEN def newround(number, ndigits=None): """ See Python 3 documentation: uses Banker's Rounding. Delegates to the __round__ method if for some reason this exists. If not, rounds a number to a given precision in decimal digits (default 0 digits). This returns an int when called with one argument, otherwise the same type as the number. ndigits may be negative. See the test_round method in future/tests/test_builtins.py for examples. """ return_int = False if ndigits is None: return_int = True ndigits = 0 if hasattr(number, '__round__'): return number.__round__(ndigits) if ndigits < 0: raise NotImplementedError('negative ndigits not supported yet') exponent = Decimal('10') ** (-ndigits) if PYPY: # Work around issue #24: round() breaks on PyPy with NumPy's types if 'numpy' in repr(type(number)): number = float(number) if isinstance(number, Decimal): d = number else: if not PY26: d = Decimal.from_float(number).quantize(exponent, rounding=ROUND_HALF_EVEN) else: d = from_float_26(number).quantize(exponent, rounding=ROUND_HALF_EVEN) if return_int: return int(d) else: return float(d) ### From Python 2.7's decimal.py. Only needed to support Py2.6: def from_float_26(f): """Converts a float to a decimal number, exactly. Note that Decimal.from_float(0.1) is not the same as Decimal('0.1'). Since 0.1 is not exactly representable in binary floating point, the value is stored as the nearest representable value which is 0x1.999999999999ap-4. The exact equivalent of the value in decimal is 0.1000000000000000055511151231257827021181583404541015625. >>> Decimal.from_float(0.1) Decimal('0.1000000000000000055511151231257827021181583404541015625') >>> Decimal.from_float(float('nan')) Decimal('NaN') >>> Decimal.from_float(float('inf')) Decimal('Infinity') >>> Decimal.from_float(-float('inf')) Decimal('-Infinity') >>> Decimal.from_float(-0.0) Decimal('-0') """ import math as _math from decimal import _dec_from_triple # only available on Py2.6 and Py2.7 (not 3.3) if isinstance(f, (int, long)): # handle integer inputs return Decimal(f) if _math.isinf(f) or _math.isnan(f): # raises TypeError if not a float return Decimal(repr(f)) if _math.copysign(1.0, f) == 1.0: sign = 0 else: sign = 1 n, d = abs(f).as_integer_ratio() # int.bit_length() method doesn't exist on Py2.6: def bit_length(d): if d != 0: return len(bin(abs(d))) - 2 else: return 0 k = bit_length(d) - 1 result = _dec_from_triple(sign, str(n*5**k), -k) return result __all__ = ['newround']