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Directory :  /proc/3/root/proc/2/task/2/root/proc/2/task/2/root/usr/share/console/

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Current File : /proc/3/root/proc/2/task/2/root/proc/2/task/2/root/usr/share/console//ps2-to-riscpc
#! /usr/bin/awk -f
# (C) 2001 Richard Atterer
# Released under the GNU General Public License, version 2 or later
#
# i386 PS/2 keymap from stdin, output on stdout converted for Acorn RiscPC

BEGIN {
  setMap_AcornRiscPC();
  print "# Automatically converted from i386 to RiscPC keycodes";
  print "";
}

# Do not warn if definition is empty anyway
/^[ \t]*keycode[ \t]+[0-9]+[ \t]*=[ \t]*$/ {
  print "# " $0;
  next;
}

{
  line = $0; outline = "";
  while (match(line, /keycode[ \t]+[0-9]+/)) {
    code = substr(line, RSTART+8, RLENGTH-8) + 0;
    if (code in k) {
      mapcode = k[code];
    } else {
      mapcode = unknownKey;
      print FNR": Warning: Cannot map input code "code > "/dev/stderr"
    }
    outline = outline substr(line, 1, RSTART-1) \
              sprintf("keycode %3d", mapcode);
    line = substr(line, RSTART + RLENGTH);
  }
  outline = outline line;
  print outline;
}

# Acorn RiscPC
function setMap_AcornRiscPC() {
unknownKey=127
k[1]=0
k[59]=1
k[60]=2
k[61]=3
k[62]=4
k[63]=5
k[64]=6
k[65]=7
k[66]=8
k[67]=9
k[68]=10
k[87]=11
k[88]=12
k[99]=13
k[70]=14
k[119]=15
k[41]=16
k[2]=17
k[3]=18
k[4]=19
k[5]=20
k[6]=21
k[7]=22
k[8]=23
k[9]=24
k[10]=25
k[11]=26
k[12]=27
k[13]=28
k[14]=30
k[110]=31
k[102]=32
k[104]=33
k[69]=34
k[98]=35
k[55]=36
k[74]=58
k[15]=38
k[16]=39
k[17]=40
k[18]=41
k[19]=42
k[20]=43
k[21]=44
k[22]=45
k[23]=46
k[24]=47
k[25]=48
k[26]=49
k[27]=50
k[28]=71
k[111]=52
k[107]=53
k[109]=54
k[71]=55
k[72]=56
k[73]=57
k[78]=75
k[58]=93
k[30]=60
k[31]=61
k[32]=62
k[33]=63
k[34]=64
k[35]=65
k[36]=66
k[37]=67
k[38]=68
k[39]=69
k[40]=70
k[43]=29
k[75]=72
k[76]=73
k[77]=74
k[42]=76
k[86]=51
k[44]=78
k[45]=79
k[46]=80
k[47]=81
k[48]=82
k[49]=83
k[50]=84
k[51]=85
k[52]=86
k[53]=87
k[54]=88
k[103]=89
k[79]=90
k[80]=91
k[81]=92
k[96]=103
k[29]=59
k[56]=94
k[57]=95
k[100]=96
k[97]=97
k[105]=98
k[108]=99
k[106]=100
k[82]=101
k[83]=102
k[125]=124
k[126]=125
k[127]=126
}

Anon7 - 2022
AnonSec Team